break and continue statement

//program with continue

#include<stdio.h>

#include<conio.h>

int main()

{

    int i;

    for (i=1;i<10;i++)

    {

        if(i==5)

        {

            continue;

        }

         printf("%d\t",i);

    }

    getch();

}

output:

here 5 is loss due to continue,it does not print 5 because it goes to increase the value of i by i++

//program with break

#include<stdio.h>

#include<conio.h>

int main()

{

    int i;

    for (i=1;i<10;i++)

    {

        if(i==5)

        {

            break;

        }

         printf("%d\t",i);

    }

    getch();

}

output:

here after finding the 5,for loop is end.

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